x^2+16x+56=-4

Solution for x^2+16x+56=-4 equation:

x^2+16x+56=-4

We move all terms to the left:

x^2+16x+56-(-4)=0

We add all the numbers together, and all the variables

x^2+16x+60=0

a = 1; b = 16; c = +60;
Δ = b2-4ac
Δ = 162-4·1·60
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-4}{2*1}=\frac{-20}{2}
=-10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+4}{2*1}=\frac{-12}{2}
=-6
$